The difficult part of this lesson is the amount of prerequisite mathematical knowledge. Students must be familiar with right triangle trigonometry, vectors, and finally, the vertical motion mathematics from the first part of the lesson.
A vector is quantity in which both the magnitude and the direction are stated. For example, I could be driving at 35 mph, which is just speed. If I am driving north 35 mph, I now have velocity, which is also a vector.
Start with the 1500 m/s problem and move slowly through the beginning. The important aspects of the drawing are shown below.
The students' drawings may not include the horizontal and vertical arrows, but they are the most important attribute of the modeling of the situation. The slanted arrow is the velocity vector of the cannonball. The horizontal arrow represents the horizontal component of the velocity vector and the vertical arrow represents the vertical component of the velocity vector. In the previous lesson, we only used the vertical component.
Simply put, we graph on a horizontal/vertical coordinate system, so we need to convert the slanted vector into a horizontal and vertical component. This is where the right triangle trigonometry comes in handy. To calculate the vertical component of the velocity evaluate:
vy = v0 sin , where v0 represent the initial velocity and represents the angle of inclination. Similarly, the horizontal component can be evaluated with vx = v0 cos .
Example:
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v0 = 1500 m/s and = 150
vy = v0 sin = 1500 sin 150 388.2 m/s
vx = v0 cos = 1500 cos 150 1477 m/s |
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These values should make sense because the cannon is fired horizontally. The cannon is angled slightly vertically, so the vertical component of velocity is smaller in comparison.
The rest of the questions on the worksheet are solved similarly to those of the past lesson.
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